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6a^2+17a+7=0
a = 6; b = 17; c = +7;
Δ = b2-4ac
Δ = 172-4·6·7
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-11}{2*6}=\frac{-28}{12} =-2+1/3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+11}{2*6}=\frac{-6}{12} =-1/2 $
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